Question

Simplify.

(1+1/3)2−2/9

Answer 1

`\left(1+(1)/(3)\right)^(2)-(2)/(9)=1+(2)/(3)+(1)/(9)-(2)/(9)\\\\=1+(6+1-2)/(9)=1(5)/(9)`

Another way to compute this is ...

`\left(1+(1)/(3)\right)^(2)-(2)/(9)=\left((4)/(3)\right)^(2)-(2)/(9)=(16)/(9)-(2)/(9)\\\\=(16-2)/(9)=(14)/(9)=1(5)/(9)`