Question

Which trigonometric ratio will not have the same value as sin A?

Answer 1

`\sin\theta=(opposite)/(hypotenuse)\\\\\cos\theta=(adjacent)/(hypotenuse)\\\\\tan\theta=(opposite)/(adjacent)`

It's an isosceles triangle, therefore AB = BC.

Let AB = BC = x abd AC = y. Then:

`opposite=adjacent=x\\hypotenuse=y\\\\\sin A=(x)/(y)\\\\\cos A=(x)/(y)\\\\\sin C=(x)/(y)\\\\\cos C=(x)/(y)\\\\\tan C=(x)/(x)=1`

Answer: C. tan C

Answer 2

correct option is d) cos C

Explanation:

Since,

`SinФ = (perpendicular)/(hypotenuses)`

`CosФ = (base)/(hypotenuses)`

`TanФ = (perpendicular)/(base)`

In triangle ABC , sides are denoted as mention in figure-1

`sin A =(x)/(z)`

`cos A =(y)/(z)`

`sin C =(y)/(x)`

`tan C =(y)/(x)`

`cos C =(x)/(z)`

hence, cos C have similar value as sin A

Therefore, correct option is d) cos C