Question

What is the molality of a solution made by dissolving 6 moles of naoh in 3 kg of water?

Answer 1

Correct answer: 2 mol/Kg

Step-by-step explanation:

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Answer 2

Answer: Molality = 2 mol/Kg or 2m

Molality is a property of a solution and is defined as the number of moles of solute per kilogram of solvent. The SI unit for molality is mol/kg or 'm'.

`Molality(m)=((Moles of solute))/((Mass of solvent in Kg))`

In our question , Solute is NaOH and solvent is water.

Moles of solute NaOH = 6 mol

Mass of solvent water = 3 kg

`Molality(m)=((6 mol))/((3 Kg))`

`Molality(m)=(2mol)/(kg)`

Molality = 2m