Question

Helen mixes a first solution, 4 liters of 40% concentrated sulfuric acid solution, with a second solution, 5 liters of a sulfuric acid solution with a stronger concentration, and the resultant solution is 9 liters of 50% concentrated sulfuric acid solution. what was the concentration, as a percent, of the second solution?

Answer 1

The percentage of the second solution would of been 10% as the total of both solutions was 50% and we already knew that the first solution had 40%

Answer 2

Answer: 58%

Step-by-step explanation:

Formula used :

`C_1V_1+C_2V_2=C_3V_3`

where,

`C_1` and
`C_2` are the concentrations of first and second solution respectively

`C_3` is the concentration of resulting solution

`V_1` and
`V_2` are the volumes of of first and second solution respectively

`V_3` is the volume of resulting solution = 9 L

Now put all the given values in the above formula, we get the concentration of resulting solution.

`(4* 40)+(5* x)=(9* 50)`

solving for x, we get

`x=58%`

The concentration of the second solution= 58%.