How many molecules are in 100. l of potassium hydroxide solution at stp?

Question

asked Jun 10, 2019 151k views

1 Answer

Basilikum · Answer 1 · 2019-06-17T04:32:34+0000

Answer : There are
2.68* 10^(24) molecules in 100 Lof potassium hydroxide(KOH) solution at stp.

Explanation : To calculate the molecules we first need to find out the moles.

One mole of an ideal gas will occupy a volume of 22.4 liters at STP (Standard Temperature and Pressure, 0°C and one atmosphere pressure).

1 mole = 22.4 L

100 L =
(100 L)* ((1mole))/((22.4 L))

100 L =
(100)* ((1mole))/((22.4))

100 L = 4.46 mole potassium hydroxide(KOH)

Now , we need to convert 4.46 mole to molecules of KOH.

1 mole = 6.02* 10^(23) molecules

4.46 moles =
(4.46 mole)* ((6.02* 10^(23)molecules))/((1 mole))

4.46 moles =
(4.46)* ((6.02* 10^(23)molecules))/((1 ))

4.46 moles =
2.68* 10^(24) molecules

There are
2.68* 10^(24) molecules in 100 Lof potassium hydroxide(KOH) solution at STP.