Question

How many molecules are in 100. l of potassium hydroxide solution at stp?

Answer 1

Answer : There are
`2.68* 10^(24) molecules` in 100 Lof potassium hydroxide(KOH) solution at stp.

Explanation : To calculate the molecules we first need to find out the moles.

One mole of an ideal gas will occupy a volume of 22.4 liters at STP (Standard Temperature and Pressure, 0°C and one atmosphere pressure).

1 mole = 22.4 L

100 L =
`(100 L)* ((1mole))/((22.4 L))`

100 L =
`(100)* ((1mole))/((22.4))`

100 L = 4.46 mole potassium hydroxide(KOH)

Now , we need to convert 4.46 mole to molecules of KOH.

`1 mole = 6.02* 10^(23) molecules`

4.46 moles =
`(4.46 mole)* ((6.02* 10^(23)molecules))/((1 mole))`

4.46 moles =
`(4.46)* ((6.02* 10^(23)molecules))/((1 ))`

4.46 moles =
`2.68* 10^(24) molecules`

There are
`2.68* 10^(24) molecules` in 100 Lof potassium hydroxide(KOH) solution at STP.