Question

Consider the reaction: 2nh3(aq)+ocl−(aq)→n2h4(aq)+h2o(l)+cl−(aq) this three-step mechanism is proposed: nh3(aq)+ocl−(aq) ⇌k1k2 nh2cl(aq)+oh−(aq) fast nh2ci(aq)+nh3(aq) ⟶k3 n2h+5(aq)+cl−−(aq) slow n2h+5(aq)+oh−(aq) ⟶k4 n2h4(aq)+h2o(l) fast part a does the mechanism sum to the reaction 2nh3(aq)+ocl−(aq)→n2h4(aq)+h2o(l)+cl−(aq)?

Answer 1

The proposed mechanism consists of three steps that need to be summed up to determine if they match the overall reaction equation.

Step-by-step explanation:

The proposed mechanism consists of three steps:

1. Step 1: nh3(aq) + ocl-(aq) <--->k1k2 nh2cl(aq) + oh-(aq) (fast)
2. Step 2: nh2cl(aq) + nh3(aq) →k3 n2h+5(aq) + cl-(aq) (slow)
3. Step 3: n2h+5(aq) + oh-(aq) →k4 n2h4(aq) + h2o(l) (fast)

To determine if the mechanism sums to the reaction 2nh3(aq) + ocl-(aq) →n2h4(aq) + h2o(l) + cl-(aq), we need to add up the overall reaction equation obtained by combining the individual steps. To determine if the mechanism sums to the reaction 2nh3(aq) + ocl-(aq) →n2h4(aq) + h2o(l) + cl-(aq), we need to add up the overall reaction equation obtained by combining the individual steps.

Answer 2

Yes, the mechanism sums to the reaction.

You add the equations, cancelling species that occur on opposite sides of the arrows.

Eq1: NH3(aq) + OCl^(-)(aq) → NH2Cl(aq) + OH^(-)(aq)

Eq2: NH2Cl(aq) + NH3(aq) → N2H5^(+)(aq) + Cl^(-)(aq)

Eq3: N2H5^(+)(aq) + OH^(-)(aq) → N2H4(aq) + H2O(l)

OA: 2NH3(aq) + OCl^(-)(aq) → N2H4(aq) + H2O(l) + Cl^(-)(aq)