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Find the values of a and b such that 1 and 4 are zeros of

f(x) = 2x^4-5x^3-14x^2+ax+b

User Kzahel
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1 Answer

5 votes
In this problem, we need to plug in the given x values for
f(x)=0 and find a and b.

When we plug in 1, we get:
2 * {1}^(4) - 5 * {1}^(3) - 14 * {1}^(2) + a * 1 + b = 0

Simplify:

2 - 5 - 14 + a + b = 0

- 17 + a + b = 0

a + b = 17

We got our first statement about the values of the variables. If we find one more we can find those 2 variables.

We have another given root: 4.

Plug it in:

2 * {4}^(4) - 5 * {4}^(3) - 14 * {4}^(2) + a * 4 + b = 0

512 - 320 - 224 + 4a + b = 0

- 32 + 4a + b = 0

4a + b = 32

Now we have our second one. We can combine them:

a + b = 17 \\ 4a + b = 32

I use elimination method which is easier here.

Multiply the top equation by -1:
- a - b = - 17 \\ 4a + b = 32

Add them up:

3a = 15

Simplify:

a = 5

Now we have a, we can plug in one of those equations to find b:

5 + b = 17

b = 17 - 5

b = 12

So, the answers are
a=5 and
b=12 .
User Dzmitry Hubin
by
8.1k points

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