Question

Find the distance between the two points A and then find the midpoint of the line segment AB.

Answer 1

The distance formula is
`√((x_2-x_1)^2+(y_2-y_1)^2)`

Our points are:

• A = (-3,-3)
• B = (4,5)

Using these points, we can solve for the distance as such:

`√((4-(-3))^2+(5-(-3))^2)\\ √(7^2+8^2)\\ √(49+64)\\ √(113)`

The distance between A and B is √113, or approximate 10.63, units.

Next, the midpoint formula is
`((x_2+x_1)/(2),(y_2+y_1)/(2))`

Using our points, we can solve for the midpoint as such:

`((4+(-3))/(2),(5+(-3))/(2))\\ \\((1)/(2),(2)/(2)) \\ \\ (0.5,1)`

The midpoint of Line AB is (0.5,1).