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Solve for x:

-10x/2+x=x+8/x

1 Answer

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The\ domain:\\D:\ x\\eq-2\ \wedge\ x\\eq0\\\\(-10x)/(2+x)=(x+8)/(x)\ \ \ \ |\text{cross multiply}\\\\(-10x)(x)=(2+x)(x+8)\\\\-10x^2=(2)(x)+(2)(8)+(x)(x)+(x)(8)\\\\-10x^2=2x+16+x^2+8x\\\\-10x^2=x^2+10x+16\ \ \ +10x^2\\\\11x^2+10x+16=0\\\\a=11,\ b=10,\ c=16\\\\b^2-4ac=10^2-4(11)(16)=100-704=-604 < 0\\\\NO\ REAL\ SOLUTION

User GianMS
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