Question

How do I solve this?

10 >= 7 + 3x and 9-4x =< 1

Answer 1

Subtract 7 on both side
Divide 3 from both sides
X should be >= to 1


Subtract 9 from both sides
Divide -4 from both sides
X should be =< 2

Answer 2

No solution

Explanation:

Solve each inequality separately

`10 \geq  7 + 3x`

Subtract 7 from both sides

`3 \geq 3x`

Divide both sides by 3

`1\geq x`

`x\leq 1`

Now solve the second inequality

`9-4x \leq  1`

Subtract 9 from both sides

`-4x \leq -8`

Divide both sides by -4. when we divide by negative number then reverse the inequality sign.

`x\geq 2`

`x\leq 1` and
`x\geq 2`

There is no intersection of both inequalities

So , No solution