Question

If we take 2.2 grams of CO2, 6.02 X 1021 atoms of nitrogen and 0.03 gram atoms of sulphur , then the molar ratio of C, N, and O is .

Answer 1

Answer : The molar ratio of C, N and O are 0.05 : 0.01 : 0.1 or 5 : 1 : 10

Explanation :

First we have to calculate the number of moles
`C,N\text{ and }O`.

(1) 2.2 grams of
`CO_2`

First we have to calculate the moles of
`CO_2`

`\text{Moles of }CO_2=\frac{\text{Mass of }CO_2}{\text{Molar mass of }CO_2}=(2.2g)/(44g/mole)=0.05moles`

Now we have to calculate the moles of carbon and oxygen.

As, 1 mole of
`CO_2` contains 1 mole of carbon

So, 0.05 mole of
`CO_2` contains 0.05 mole of carbon

The number of moles of carbon (C) = 0.05 mole

As, 1 mole of
`CO_2` contains 2 mole of oxygen

So, 0.05 mole of
`CO_2` contains
`2* 0.05=0.1` mole of oxygen

The number of moles of oxygen (O) = 0.1 mole

(2)
`6.02* 10^(21)` atoms of nitrogen.

As,
`6.02* 10^(23)` atoms of nitrogen present in 1 mole of nitrogen

So,
`6.02* 10^(21)` atoms of nitrogen present in
`(6.02* 10^(21))/(6.02* 10^(23))=0.01` mole of nitrogen

The number of moles of nitrogen (N) = 0.01 mole

From this we conclude that, the molar ratio of C, N and O are:

C : N : O = 0.05 : 0.01 : 0.1

or,

C : N : O = 5 : 1 : 10

Therefore, the molar ratio of C, N and O are 0.05 : 0.01 : 0.1 or 5 : 1 : 10

Answer 2

Answer: -

5 : 1 : 3

Explanation: -

Mass of CO₂ = 2.2 g

Molar mass of CO₂ = 44 g / mol

Number of moles of CO₂ =
`(Mass)/(Molar mass)`

=
`(2.2)/(44)`

= 0.05 mol

Number of atoms of nitrogen = 6.02 x 10²¹

Number of moles of nitrogen =
`(Number of atoms of nitrogen)/(Avogadro's number)`

=
`(6.02x1021)/(6.02x1023)`

= 0.01 mol

0.03 gram atom of sulphur means 0.03 moles of sulphur.

Thus the mole ratio of CO₂ : N : S = 0.05 : 0.01 : 0.03

= 5 : 1 : 3