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Randolph has 8 ties, 6 pairs of pants, and 4 dress shirts. how many days could he possibly gowithout wearing the same combination of these three items?

Randolph has 8 ties, 6 pairs of pants, and 4 dress shirts. how many days could he possibly gowithout wearing the same combination of these three items?
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Randolph has 8 ties, 6 pairs of pants, and 4 dress shirts. how many days could he possibly gowithout wearing the same combination of these three items?

User Arthur Skirvin
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1 Answer

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(8C1)(6C1)(4C1) = 8 x 6 x 4 = 192 unique combinations.

User Smooth
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