Question

What is the vertex of the quadratic function given by the equationf(x)=-(x+3)^2+5

Answer 1

`\text{The vertex formula of}\ f(x)=ax^2+bx+c:\\\\f(x)=a(x-h)^2+k\\\\(h,\ k)-vertex`

`\text{We have}\ f(x)=-(x+3)^2+5=-(x-(-3))^2+5`

`\text{Therefore your answer is}\ (-3,\ 5)`