Question

PLEASE HELP
**ONLY MATH HELPERS**

Answer 1

Perimeter of ABDE = 2+6+2+6 = 16

Perimeter of BCD:

Length BC = sqrt(3^2+4^2)=sqrt(9+16)=sqrt(25) = 5 [using Pythagoras]

Length CD = Length BC = 5

Length BD = 6

Perimeter of BCD = 5+5+6 = 16

=>

ratio of perimeters = 16:16 = 1:1

Area of figure

= area of rectangle + area of triangle

= 2*6 + 6*4/2

= 12+12

=24