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Terrence walks at a pace of 2 mi/h to the theater and watches a movie for 2 hours and 15 min he rides a bus back home at 40 mi/h the entire trip takes 3.5 hours how far is his house from the theater

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Solution:

Let the distance of house from the theater be x miles.

Total travelling time
=3.5-2.25=1.25 Hr

Then average speed
=(Distance)/(Time)= (2x)/(1.25)\\

Terrence walks at a pace of 2 mi/h to the theater and back home at 40 mi/h.

So Average Speed
=(2+40)/(2)= 21\\ mi/hr

Both the average speed should be equal. So we can write


(2x)/(1.25)=21\\ \\ 2x=1.25*21\\ \\ x=13.125\\

Hence the distance from home is 13.125 miles.

User Grechut
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