The equation for speed is:
![S =(d)/(t)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/u5p3nbnf30ecgfzipp4jvtzwhtxfaoxxis.png)
The student ran 100 meters in 11 seconds. Our distance is 100 meters and our time is 11 seconds.
![S =(100m)/(11s)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/p9h9ciduw2fd8sxpf1qc75435y6fjwc5bn.png)
When we solve we get the following:
![S = 9.09m/s](https://img.qammunity.org/2019/formulas/mathematics/middle-school/mw4q26ulaqpce7bb0oqxqmmh86a5w9y4td.png)
I am guessing since you were given the unit conversion of 1 mile = 1609 meters, you need to answer in miles per hour. If you do, you will need to use dimensional analysis:
![(9.09m/s)/(1) *(1mi)/(1609m) *(3600s)/(1hr) =(32724mi)/(1609hr) = 20.34mi/hr](https://img.qammunity.org/2019/formulas/mathematics/middle-school/ah4rvq1gaj4z18wj0jjknht8wlw07pqk7c.png)
All of the units except miles and hour cancel out, which makes this problem valid. Your answer in mph (mi/hr) would be:
20.34 miles per hour