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Cross section of a solid circular rod is subject to a torque of t = 2.7 kn⋅m . if the diameter of the rod is d = 8 cm , what is the maximum shear stress?
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Cross section of a solid circular rod is subject to a torque of t = 2.7 kn⋅m . if the diameter of the rod is d = 8 cm , what is the maximum shear stress?

User UberJason
by
7.4k points

1 Answer

4 votes
Shear Stress= Force along the tangent/ Area
= 2700/π*r^2
=2700/3.14*16
=54
User Invisible Arrow
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8.2k points
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