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At most, Keith can spend $90 on sandwiches and chips for a company lunch. He already bought chips for $15 and will buy sandwiches that cost $6 each. The inequality 15 + 6s ≤ 90 represents the described cost, where s is the maximum number of sandwiches that could be bought. What is the maximum number of sandwiches Keith can buy?

2 Answers

4 votes

Answer:

12

Explanation:

User Tibor
by
4.7k points
4 votes

It is given in the question that,

At most, Keith can spend $90 on sandwiches and chips for a company lunch. He already bought chips for $15 and will buy sandwiches that cost $6 each. The inequality


15 + 6s \leq 90

represents the described cost, where s is the maximum number of sandwiches that could be bought.

Now we have to solve for s, and for that, we first subtract 15 to both sides, that is


6s\leq  75

Dividing both sides by 6


s\leq  12.5

So the maximum number of sandwiches Keith can buy is 12.

User Vtasca
by
4.6k points
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