145k views
3 votes
In triangle ABC angle A - angle B =15 , angle B - angle C = 30, find angle B , angle A , angle C

1 Answer

3 votes

∠A - ∠B = 15 → ∠A = 15 + ∠B

∠B = ∠B

∠B - ∠C = 30 → ∠C = ∠B - 30

Since ABC is a triangle, then their sum equals 180°

∠A + ∠B + ∠C = 180

(15 + ∠B) + (∠B) + (∠B - 30) = 180

3∠B - 15 = 180

3∠B = 195

∠B = 65

∠A = 15 + ∠B → ∠A = 15 + 65 → ∠A = 80

∠C = ∠B - 30 → ∠C = 65 - 30 → ∠C = 35


Answer: ∠A = 80, ∠B = 65, ∠C = 35

User Ahron
by
8.5k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories