Question

(b^2+2)(6b^5-10) could someone help me with this? im not very good with math and cant figure out how to do it.

Answer 1

(b^2+2)(6b^5-10)

FOIL

=b^2 * 6b^5 + b^2 (-10) + 2(6b^5) + 2(-10)

= 6b^7 - 10b^2 + 12b^5 - 20

= 6b^7 + 12b^5 - 10b^2 - 20

Answer

6b^7 + 12b^5 - 10b^2 - 20