Question

How much heat is required to raise the temperature of 100 grams of water from, 25c to 82 c?

Answer 1

Answer:- 23.8 kJ of heat is required to raise the temperature of water.

Solution:- We have been given with grams of water, it's initial and final temperature and asked to calculate the heat required to raise it's temperature. Here, lower degree C water is changing into higher degree C water. So, the formula used to calculate the heat is:

`q=mc\Delta T`

Where, q is the heat energy, m is mass, c is specific heat of water and delta T is change in temperature.

m = 100 grams

`\Delta T` = 82 - 25 = 57 degree C

`c=4.184(J)/(g.^0C)`

q=?

Let's plug in the values in the formula and do the calculations:

`q=100*4.184*57`

q = 23848.8 J or 23.8 kJ

So, 23.8 kJ of heat is required to raise the temperature of 100 g of water from 25 to 82 degree C.