Question

The winning times (in seconds) in a speed-skating event for men can be represented by the formula T = 46.12 - 0.094x where x represents the year, with x=0 corresponding to 1920. (For example in 1992, x would be 1992 - 1920 = 72.) According to the formula, what was the winning time in 1983? Round to the nearest hundredth.

Answer 1

The winning time in 1983 was approximately 40.20 seconds.

Step-by-step explanation:

To find the winning time in 1983 using the given formula T = 46.12 - 0.094x, where x represents the year, we need to substitute x = 1983 - 1920 = 63 into the equation.

So, T = 46.12 - 0.094(63) = 46.12 - 5.922 = 40.198 seconds.

Therefore, the winning time in 1983 was approximately 40.20 seconds.

Answer 2

The given question is:

The winning times (in seconds) in a speed-skating event for men can be represented by the formula T = 46.12 - 0.094x where x represents the year, with x=0 corresponding to 1920.

In 1983,

`x = 1983 -1920 = 63`

Substituting 63 for x in the given equation, we will get

`T = 46.12 -0.094(63) =40.198= 40.20`