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Chase got a lab report back with a "-5.0% error" written in red on it. He had determined the boiling point of an unknown liquid to be 45°C. What is the correct boiling point of the unknown liquid?

Chase got a lab report back with a "-5.0% error" written in red on it. He-example-1
User Milovan
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Answer: The boiling point of the liquid is 47.368°C.

Step-by-step explanation: The percent error is a tool used to determine the precision of the calculations.


\%\text{ error}=\frac{(\text{Experimental Value - Theoretical Value})}{\text{Theoretical Value}}*100

Here, we need to calculate the Theoretical Value,

Experimental value = 45°C

% error = -5.0%

Let theoretical value be "x"


-5.0=((45-x))/(x)*100


-5x=(45-x)* 100\\-5x=4500-100x\\95x=4500\\x=47.368\°C

The correct boiling point of the unknown liquid is 47.368°C

User Jhocking
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