139k views
3 votes
What's the axis of symmetry for y=-3x^2+1

User Jamesnvc
by
8.1k points

1 Answer

4 votes

y = -3x^2 + 1 is a quadratic with a = -3, b = 0 and c = 1.

The equation of the axis of symmetry is x = -b/(2a). Here, that comes out to:

x = 0 / (2*[-3]), or x = 0 (answer)

User Benjamin James
by
8.2k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories