139k views
3 votes
What's the axis of symmetry for y=-3x^2+1

User Jamesnvc
by
8.1k points

1 Answer

4 votes

y = -3x^2 + 1 is a quadratic with a = -3, b = 0 and c = 1.

The equation of the axis of symmetry is x = -b/(2a). Here, that comes out to:

x = 0 / (2*[-3]), or x = 0 (answer)

User Benjamin James
by
8.2k points

No related questions found