Question

What’s X2 25/289 ? For real number in math

Answer 1

we are given

`x^2= (25)/(289)`

Firstly, we will find all possible factors of 25 and 289

25=5*5

289=17*17

so, we get

`x^2= (5*5)/(17*17)`

`x^2= (5^2)/(17^2)`

Since, we have to solve for x

so, we can take sqrt both sides

`√(x^2)= -\sqrt{(5^2)/(17^2) }`

`√(x^2)= \sqrt{(5^2)/(17^2) }`

now, we can simplify both

`x=-(5)/(17)`

`x=(5)/(17)`

so, solutions are

`x=-(5)/(17)`

`x=(5)/(17)`................Answer