Question

A car traveling at 22.4 m/s skids to a stop in 2.25s. Determine the skidding distance of the car

Answer 1

`\bold{Hello}`


Given :

u = 22.4 m/s

v = 0

t = 2.25

s = ?



applying the equation of motion :



`\bold{v = u + at}`


putting the values , we get value of

`\bold{a = 9.955 m/{s}^2}`


putting value of a in other equation . :-


=>
`\bold{v^2 = u^2 + 2as}`


by solving this , we get stopping distance :-



`\bold{\large{s = 25.201 m}}`






Hope It Helps You. ^_^

Answer 2

Hello!

A car traveling at 22.4 m/s skids to a stop in 2.25 s. Determine the skidding distance of the car

We have the following data:

a (acceleration) = ? (in m/s²)

t (time) = 2.25 s

Vf (final velocity) = 22.4 m/s

Vi (initial velocity) = 0 m/s

We apply the data to the formula of the hourly function of the velocity, let's see:

`V_f = V_i + a*t`

`22.4 = 0 + a*2.25`

`22.4 = 2.25\:a`

`2.25\:a = 22.4`

`a = (22.4)/(2.25)`

`\boxed{a \approx 9.955\:m/s^2}\Longrightarrow(acceleration)`

*** The distance traveled ?

We have the following data:

Vi (initial velocity) = 0 m/s

t (time) = 2.25 s

a (average acceleration) = 9.955 m/s²

d (distance interval) = ? (in m)

By the formula of the space of the Uniformly Varied Movement, it is:

`d = v_i * t + (a*t^(2))/(2)`

`d = 0 * 2.25 + (9.955*(2.25)^(2))/(2)`

`d = 0 + (9.955*5.0625)/(2)`

`d \approx (50.4)/(2)`

`\boxed{\boxed{d \approx 25.2\:m}}\longleftarrow(distance)\:\:\:\:\:\:\bf\blue{\checkmark}`

*** Another way to solve:

We have the following data:

Vf (final velocity) = 22.4 m/s

Vi (initial velocity) = 0 m/s

a (average acceleration) = 9.955 m/s²

d (distance interval) = ? (in m)

Since we do not need to know the time elapsed during the movement, we apply the data of the question to the Equation of Torricelli, let us see:

`V_f^2 = V_i^2 + 2*a*d`

`22.4^2 = 0^2 + 2*9.955*d`

`501.76 = 19.91\:d`

`19.91\:d = 501.76`

`d = (501.76)/(19.91)`

`\boxed{\boxed{d \approx 25.2\:m}}\longleftarrow(distance)\:\:\:\:\:\:\bf\blue{\checkmark}`

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`\bf\purple{I\:Hope\:this\:helps,\:greetings ...\:Dexteright02!}`