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|x-11|= 5x +10 how do I solve this

User Alliswell
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2 Answers

4 votes

With absolute value equations, we have:


|x| = \left\{ \begin{array}{ll} -x & \quad x \leq 0 \\ x & \quad x > 0 \end{array} \right.

So, if x-11 is less than 0, we have -x+11, and if x-11 is greater than 0, we have x-11. Solving these two cases:


-x+11=5x+10 \implies \\-6x=-1\implies \\x=(1)/(6)\\\\x-11=5x+10 \implies \\-4x=-1 \implies \\x=(1)/(4)

So, our two solutions are 1/6 and .25, and all absolute value equations are solved like this.

User Recnac
by
5.3k points
1 vote

the absolute value of anything is a positive number so

lx-11l= 5x+10

x+11=5x+10

-x -x

11=4x+10

-10 -10

1=4x.

1/4=4x/4

1/4=x

1 divided by four = .25

so x =.25

User Vala
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4.7k points