Question

The length of a rectangle is 5 cm more than its width. The perimeter is 82 cm. Find the length of the rectangle.

Answer 1

We will represent the length of the rectangle as
`l` and the width as
`w`.

From this problem, we can say
`l = w + 5`. We can also deduct an equation from the second sentence:

`2l + 2w = 82`

`2(w + 5) + 2w = 82` (from substitution)

`2w + 10 + 2w = 82`

`4w = 72`

`\boxed{w = 18}`

Using this value for
`w`, we can find
`l`:

`l = 18 + 5`

`\boxed{l = 23}`

The length of the rectangle is 23 cm and the width of the rectangle is 18 cm.