Question

A ball is thrown from 4 feet off the ground with a vertical velocity of 30 feet per second.

Write an equation to model the height of the ball. The equation is h = -16t 2 + 30t + 4.

Please make a table for the height in feet when the time is:
0
0.5
1
1.5
and find the height when the time is 2 seconds.

Thanks so much guys!!

Answer 1

Important: It's h = -16t^2 + 30t + 4, where " ^ " indicates exponentiation.

The units of measurement of h(t) are "feet."

Note that if time t = 0, h(0) = 4. This is the "initial value" of your function, the height off the ground of the ball at the very beginning.

As time progresses, the ball will travel skyward, slow down, momentarily stop moving, and then fall to the ground at an increasingly faster rate.

Here's the table of t and h values that you wanted:

t (sec) h(t) (feet)

0 4

0.5 15

1 18

1.5 4

2.0 0

Note that the ball must stop moving when it hits the ground. According to this table, that happens at time 2 sec. The max height reached by the ball is in the neighborhood of 18 ft, after 1 sec of upward travel.

Answer 2

when the time is 2 seconds, the height is 0 feet, meaning the ball is back on the ground.

Explanation:

Please see attached for table.

When the time is 0 seconds, the height is 4 feet.

The ball ascends in 0.5 seconds and reaches maximum height of 18 feet in 1 second. At 1.5 seconds, the ball descends and reaches minimum height of 0 feet (on the ground) in 2 seconds.