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Need help with B and C

Need help with B and C-example-1
User Watery
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1 Answer

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From the definition of the sine function

... sin(51°) = 9/c

Solving for c gives

... c = 9/sin(51°) ≈ 11.58

From the definition of the tangent function

... tan(51°) = 9/b

Solving for b gives

... b = 9/tan(51°) ≈ 7.29

_____

Check

b² +9² = c²

7.29² +9² = 134.12 = 11.58² . . . . yes

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The mnemonic SOH CAH TOA can help you remember

... Sin = Opposite/Hypotenuse

... Cos = Adjacent/Hypotenuse

... Tan = Opposite/Adjacent

User Zorrocaesar
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5.9k points