Alright, lets get started.
The length of first fence =
![(15)/(16)](https://img.qammunity.org/2019/formulas/mathematics/high-school/f305z2x1fwox10tvnzkbd8tnqksb1s1pqq.png)
The length of second fence =
![(7)/(8)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/heyfbusvelejms7vfs1jao2x26yjrbbp8v.png)
The length of third fence =
![(7)/(16)](https://img.qammunity.org/2019/formulas/mathematics/high-school/1yppuw171es84iv6hlr7yx9ctb2ws6a87f.png)
Total length of all three fence =
![(15)/(16)+(7)/(8)+(7)/(16)](https://img.qammunity.org/2019/formulas/mathematics/high-school/253k1p66tgt87qf5h4yed2clnde3mj1vno.png)
For adding them, we need to first make common denominator
Total length of all three fence =
![(15)/(16)+(2*7)/(2*8)+(7)/(16)](https://img.qammunity.org/2019/formulas/mathematics/high-school/wc7hgf9zv9ixfgo2tavx8a3wqa1811ybc8.png)
Total length of all three fence =
![(15)/(16)+(14)/(16)+(7)/(16)](https://img.qammunity.org/2019/formulas/mathematics/high-school/6feu0dwwh304nz75nqyk3rvly5vklf8wjl.png)
Now we have common denominator, so
Total length of all three fence =
![(15+14+7)/(16)](https://img.qammunity.org/2019/formulas/mathematics/high-school/5np1xt18zjsanbdcu4z3cxbxfb0vbxn8ki.png)
Total length of all three fence =
![(36)/(16)](https://img.qammunity.org/2019/formulas/mathematics/high-school/y0hwd2tclor1ltu5ru4j9vs3qrgjpk0n2b.png)
36 and 16 could be simplified with 4, so
Total length of all three fence =
: Answer
Hope it will help :)