Question

Find the factorization of the polynomial below.

81x^2+7x+16

A. (9x + 8)(9x + 8)
B. (9x + 8)(9x - 8)
C. (9x + 4)(9x - 4)
D. (9x + 4)(9x + 4)

Answer 1

OptionD is the answer..!!
Hope this helps u.!!

Answer 2

The given Polynomial is

`\rightarrow 81x^2+7x+16`

------------------------------(1)

Comparing with general equation of Quadratic

ax²+bx+c=0

The roots or factorization of this polynomial is possible only when

`D\geq b^2-4ac`

In equation 1,

`D=(7)^2-4 * 81 * 16\\\\D=49-5184\\\\D= -5135\\\\D<0`

So, Real factors of this Polynomial is not Possible.

Complex roots is given by

`\rightarrow x=(-b\pm √(D))/(2a)\\\\x=(-7 \pm √(-5135))/(2 * 81)\\\\x=(-7 \pm√(-5135))/(162)`