Question

1-20 evaluate the expression below of the given values. If you can explain it to me i’m so appreciated

Answer 1

To solve 1-20, you plug in the number for the variable that the variable is equal to e.i. a) x = -3 so you plug -3 in every place there is an x

-2(-3)^2 - 3(-3) + 1

-2(9) +9 + 1

-18 +10

-8
The solution to a) is -8.

Please leave a comment and let me know if you also need help with b-d or if you understand.

Answer 2

a) -8

b) -56

c) 3

d) 6

Explanation:

(a). The expression is given by,

`\Rightarrow -2x^2-3x+1`

Now, substitute the the value of x = 3 in the expression

`\Rightarrow -2*(-3)^2-3*(-3)+1`

`\Rightarrow -8`

(b). The expression is given by,

`\Rightarrow 8-(3x-2)^2`

Now, substitute the the value of x = -2 in the expression

`\Rightarrow 8-(3*(-2)-2)^2`

`\Rightarrow -56`

(c). The expression is given by,

`\Rightarrow (-3)/(k+2)`

Now, substitute the the value of k = -3 in the expression

`\Rightarrow (-3)/(-3+2)`

`\Rightarrow 3`

(d). The expression is given by,

`\Rightarrow (15m)/(n+1)-m^2+n`

Now, substitute the the value of m = 1 and n = 2 in the expression

`\Rightarrow (15*1)/(2+1)-1^2+2`

`\Rightarrow 6`

Hence, This is the required solution.