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How many moles of nitrogen gas are there in 6.8 liters at room temperature and pressure (293 K and 100 kPa)?
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How many moles of nitrogen gas are there in 6.8 liters at room temperature and pressure (293 K and 100 kPa)?

User Ggilberth
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1 Answer

5 votes
PV=vRT
P-preassure
V -volume
v-moles
R -const
T-temp

v=PV/RT=0,98*6,8/0,082*293=

i transformed kPascals into pascals and then into atm

100kpa=0,98atm
User Tarka
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