What is the pressure in a 20.0 l container filled with 0.896 moles of nitrogen gas at a temperature of 42 oc?

Question

asked Dec 13, 2019 19.3k views

1 Answer

Bhargav Ponnapalli · Answer 1 · 2019-12-18T22:42:36+0000

Hello!

We have the following data:

P (Pressure) =? (atm)

V (volume) = 20.0 L

n (mol number) = 0.896 mol

R (gas constant) = 0.082 atm.L / mol.K

T (temperature) = 42 °C (in SI the temperature is given in Kelvin, needs to turn into Kelvin)

TK = TºC + 273.15

TK = 42 + 273.15

TK = 315.15

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Applying the data to the Clapeyron equation, we have:

P*V = n*R*T

P*20.0 = 0.896*0.082*315.15

$20.0\:P = 23.1547008$

P = (23.1547008)/(20.0)

$\boxed{\boxed{P \approx 1.157\:atm}}\end{array}}\qquad\checkmark$

I Hope this helps, greetings ... DexteR!