Question

A certain liquid leaks out of a container at the rate of k liters for every x hours. if the liquid costs $6 per liter, what is the cost, in dollars, of the amount of the liquid that will leak out in y hours?

Answer 1

If k liters of liquid leak out every x hours, we can compute the amount of liters that leak out every hour:

`x \text{ hours} = k \text{ liters} \implies 1 \text{ hour} = \frac{x \text{ hours}}{x} = (k)/(x) \text{ liters}`

So, with each passing hour we lose
`(k)/(x)` liters. So, in
`y` hours we lose

`y * (k)/(x) = (ky)/(x)` liters.

Each of this liters costs 6$, so we lose a total of

`6 * (ky)/(x) = (6ky)/(x)` dollars.