Question

5/7^3 = 5(7^x)
Thank you for helping!!

Answer 1

When solving this equation you get x = -3.

To solve this, simply follow the order of operations for solving.

`(5)/(7^(3)) = 5(7^(x) )` ----> start by dividing both sides by 5

`(1)/(7^(3)) = (7^(x) )` -----> Now you can transform the front side of the equation to use negative exponents.

`7^(-3) = 7^(x)`

Since both x and -3 are the powers of x, we can eliminate the 7 and just make the exponents equal.

-3 = x