85.8k views
2 votes
Solve 2x^2 +16x+50=0

User Covati
by
8.4k points

1 Answer

2 votes


2x^2 +16x+50=0\ \ \ \ \ |:2\\\\x^2+8x+25=0\\\\x^2+2\cdot x\cdot4+25=0\ \ \ \ |+4^2\\\\\underbrace{x^2+2\cdot x\cdot4+4^2}_((a+b)^2=a^2+2ab+b^2)+25=4^2\ \ \ \ \ |-25\\\\(x+4)^2=16-25\\\\(x+4)^2=-9 < 0-NO\ REAL\ SOLUTION


COMPLEX\ SOLUTIONS\\\\(x+4)^2=-9\to x+4=\pm√(-9)\\\\x+4=-3i\ \vee\ x+4=3i\ \ \ \ |-4\\\\x=-4-3i\ \vee\ x=-4+3i

User Amanada Smith
by
8.0k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories