Question

Triangle RST has vertices R(2, 0), S(4, 0), and T(1, –3). The image of triangle RST after a rotation has vertices

R'(0, –2), S'(0, –4), and T'(–3, –1). Which rule describes the transformation?

Answer 1

R(2, 0)
R'(0,-2)

Let's say 2 and -2 are A and 0 is B.
Then R(A, B)
R'(B, -A)

This is rotation by 270 degrees about the origin.

Answer 2

By the rotation rule of 270 of counter clock wise ( x ,y) →→ ( y , -x )

Explanation:

Given : Triangle RST has vertices R(2, 0), S(4, 0), and T(1, –3). The image of triangle RST after a rotation has vertices R'(0, –2), S'(0, –4), and T'(–3, –1).

To find : Which rule describes the transformation.

Solution : We have given

Parent vertices R(2, 0), S(4, 0), and T(1, –3).

Transformed vertices R'(0, –2), S'(0, –4), and T'(–3, –1).

By the rotation rule of 270 of counter clock wise ( x ,y) →→ ( y , -x )

R(2, 0)→→ R'(0, –2)

S(4, 0)→→ S'(0, –4)

T(1, –3)→→ T'(–3, –1).

We can see y coordinate change in to x and x coordinate become - y.

Therefore ,By the rotation rule of 270 of counter clock wise ( x ,y) →→ ( y , -x )