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If p and q are both true, then which of the following statements has the same truth-value as ~p → q?

A) ~p ∧ ~q
B) ~p ∨ ~q
C) p ∧ ~q
D) ~q → p

User Hargrovm
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1 Answer

1 vote

If p and q are both true, then


\\eg p \implies q

is an implication of the form


F \implies T

which is true, because every implication starting with false is true, i.e.


F \implies T = T,\quad F \implies F = T

So, we're looking for an expression evaluating to true. Let's see what we have:

A) is an AND proposition. Logical AND is true only if both parts are true. So, you have


\\eg P \land \\eg Q = F \land F = F

So it's not the right option.

B) is an OR proposition. Logical OR is true whenever one of the two parts is true. So, you have


\\eg P \lor\\eg Q = F \lor F = F

So it's not the right option.

C) is again an AND proposition. You have


P \land \\eg Q = T \land F = F

So this is not the right option.

D) Finally, the last one is again an implication, and again it starts with false:


\\eg Q \implies P = F \implies T = T

So this is true, and thus is the correct option.

User Genericrich
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