Question

A right triangle has side length 9,40, and 41 as shown below.

Answer 1

`\sin\theta=(opposite)/(hypotenuse)\\\\\cos\theta=(adjacent)/(hypotenuse)\\\\\tan\theta=(opposite)/(adjacent)\\\\\text{We have}\\\\opposite=40\\adjacent=9\\hypotenuse=41\\\\\text{substitute}\\\\\tan M=(40)/(9)\\\\\sin M=(40)/(41)\\\\\cos M=(9)/(41)`