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Checking account A charges a monthly fee of $10 and a per-check fee of $0.10, and checking account B charges a monthly fee of $12 and a per-check fee of $0.05. How many checks would a person have to write for the two accounts to cost the same?

A. 35

B. 50

C. 55

D. 40

2 Answers

3 votes

Final answer:

To determine the number of checks that would make the two accounts cost the same, we need to set up an equation. Let x be the number of checks. For account A, the cost is $10 + $0.10x. For account B, the cost is $12 + $0.05x. We can set these two costs equal to each other and solve for x. Therefore, a person would have to write 40 checks for the two accounts to cost the same.

Step-by-step explanation:

To determine the number of checks that would make the two accounts cost the same, we need to set up an equation. Let x be the number of checks. For account A, the cost is $10 + $0.10x. For account B, the cost is $12 + $0.05x. We can set these two costs equal to each other and solve for x:



$10 + $0.10x = $12 + $0.05x



Subtract $0.05x from both sides:



$0.05x = $2



Divide both sides by $0.05:



x = 40



Therefore, a person would have to write 40 checks for the two accounts to cost the same.

User Serge Kvashnin
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2 votes

Best Answer: Account A would have to write 30 checks to equal a total amount of 13.00 for the monthly fee.

30 checks x .10 equal 3.00 dollars + 10 dollar monthly fee = 13.00.

Account B would have to write 20 checks to equal a total amount of 13.00 for the monthly fee.

20 checks x .05 equal 1.00 dollars + 12.00 dollar monthly fee = 13.00.

User GANI
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5.6k points