Question

A 5.5 kg box is pushed across the lunch table. The acceleration of the box is 4.2 m/s2. What was the net force applied to the box? A) 1.3 N B) 1.31 N C) 9.7 N D) 23.1 N

Answer 1

The net force applied to a 5.5 kg box with an acceleration of 4.2 m/s2 is calculated using Newton's second law (F = m × a), resulting in a force of 23.1 N.

Step-by-step explanation:

The question involves finding the net force applied to a box with a mass of 5.5 kg that is accelerating at 4.2 m/s2. According to Newton's second law of motion, the net force applied to an object is equal to the mass of the object multiplied by its acceleration (F = m × a).

Using the formula, we can calculate:
F = m × a = 5.5 kg × 4.2 m/s2 = 23.1 N.

Therefore, the correct answer is D) 23.1 N.

Answer 2

The sum of all forces=m(mass) times a(acceleration). F=5.5(kg)*4.2(m/s^2)= 23.1N or D.