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9 votes
9 votes
HELP PLEASE PLEASE 100 POINTS

HELP PLEASE PLEASE 100 POINTS-example-1
User Bart Van Den Burg
by
2.4k points

2 Answers

10 votes
10 votes

Answer:

x = 29

z = 13

Angle RIG = 59 deg.

Angle ZIM = 41 deg.

Explanation:

So we know that angle ZIA = angle MIG

3x - 56 = x + 2

We can solve this equation

2x = 58

x = 29

Next, angle RIG + GIM = 90 degrees.

So if we do 4z + 7 + x + 2 = 90 degrees when x = 29, we can plug x in.

4z + 7 + 29 + 2 = 90 degrees

4z + 38 = 90 degrees

4z = 90 - 38

4z = 52

z = 13

Angle RIG = 4z + 7

We know that z = 13

4 * 13 + 7 = 52

Therefore RIGZ = 52 degrees.

Angle ZIM = x + 2

x = 39 + 2

x = 41

User Eirikir
by
2.7k points
20 votes
20 votes

Answer:

x=29

z=13

<RIG= 59°

<ZIM=31°

step-by-step explanation:

(vertically opposite angles)

<ZIA=<MIG

3x-56=x+2

group like terms

3x-x=56+2

2x=58

divide both side by the coefficient of x

2x/2=58/2

x=29

<RIG+<GIM=90°

4z+7+x+2=90°

where x=29

4z+7+29+2=90°

4z+38=90°

make for 4z the subject

4z=90°-38°

4z=52°

let z stand alone

4z/4=52/4

z=13

<RIG=4z+7

where z=13

4(13)+7

52°=RIGZ

<ZIM=x+2

where x =39+2

x=31°

User Calben
by
2.8k points