Sin^2x/cos^2 + sinxcscx = sec^2x Identify it, please explain so I know how you did it, thanks

asked May 25, 2019 181k views

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$(sin^2x)/(cos^2x) + sin x *cscx\\ tan^2x + (sin x)/(sin x) \\ tan^2x + 1\\ sec^2x$

(sin^2x)/(cos^2x) = tan^2x

csc x = (1)/(sinx)

tan^2x + 1 = sec^2x

Icycool answered May 29, 2019

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