Question

Number four says “What is the instantaneous acceleration at t = 10 s?”

Can you guys help with these? I will give 20 points! Please help if you can give me the correct answers!

Answer 1

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Answer 2

Answer:Explained

Step-by-step explanation:

For

3)at t=0 v=4 m/s

and t=2 v=5.2 m/s

acceleration is \frac{v-u}{t}=\frac{5.2-4}{2-0}=0.6m/s^2[/tex]

5)Constant negative acceleration because slope of the graph is negative and constant.

4)
`a=(16-14)/(11-10)`

`a=2 m/s^2`

7)changing negative acceleration because slope of parabola is decreasing to zero and slope of V-t graph give acceleration

9)changing positive acceleration as the slope of graph is increasing.

10)at t=2 acceleration is
`-2m/s^2` because after t=4 slope is increasing and positive.