Question

The area of a rectangle is 70 in 2 and the length of the rectangle is 3 in. Longer than the width

Answer 1

Alright, lets get started.

I hope, the dimensions of rectange are asked in this question.

Suppose the width of rectangle = x in

Given that length of the rectangle is 3 in longer than the width.

It means length of the rectangle = (x+3) in

Now, the area of the rectangle = lenght * width

area of the rectangle =
`x * (x+3)`

area of the rectangle =
`x^2+3x`

The area of a rectangle is 70 in square (given in question)

Equalling both areas

`x^2 + 3x = 70`

Subtracting 70 in both sides

`x^2 + 3x - 70 = 70 - 70`

`x^2 + 3x - 70 = 0`

Factoring

`(x-7)(x+10) = 0`

It will give two values of x

x = -10 (which is not possible because length could not be negative)

x = 7

Means width
`= 7 in`

length
`= 7 + 3 = 10 in`

Means the dimensions of rectangle are 7 in and 10 in. : Answer

Hope it will help :)