What is the remainder when (2x^3+4x^2-32x+18)÷(x-3) A) 2 B) 12 C) 96 D) 110

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asked Jul 3, 2019 154k views

2 Answers

Michael McLoughlin · Answer 1 · 2019-07-07T06:25:51+0000

C) 96
(2x^3+4x^2-32x+18)÷(x-3)
First divide the polynomials, since the last term in the resulting expression is a fraction, the numerator of the fraction is the remainder.

What is the remainder when (2x^3+4x^2-32x+18)÷(x-3) A) 2 B) 12 C) 96 D) 110

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