Question

a ball of mass 4 kg is initially traveling at 2 meters per second and has a 5 Newton Force applied to it for 3 seconds what's the final velocity of the ball

Answer 1

`a=(F)/(m)=(5N)/(4kg)=1.2(m)/(s^2)`

`\Delta v = a \cdot t = 1.2 (m)/(s^2) \cdot 3 s = 3.6 (m)/(s)`

`v = v_0 + \Delta v = 2 + 3.6 = 5.6 (m)/(s)`