Question

(a) the temperature on a warm summer day is 87 °f. what is the temperature in °c? (b) many scientific data are reported at 25 °c. what is this temperature in kelvins and in degrees fahrenheit? (c) suppose that a recipe calls for an oven temperature of 400 °f. convert this temperature to degrees celsius and to kelvins. (d) liquid nitrogen boils at 77 k. convert this temperature to degrees fahrenheit and to degrees celsius.

Answer 1

(a) The temperature in degree Celsius is,
`30.5^oC`

(b) The temperature in Kelvin and in degree Fahrenheit is, 298K and
`77^oF` respectively.

(c) The temperature in degree Celsius and Kelvin is,
`204.4^oC` and 477.4 K respectively.

(d) The temperature in degree Fahrenheit and Celsius is,
`-320.8^oF` and
`-196^oC` respectively.

Explanation :

The conversion used for the temperature from Fahrenheit to degree Celsius is:

`^oC=(^oF-32)* (5)/(9)`

where,

`^oF` = temperature in Fahrenheit

`^oC` = temperature in centigrade

The conversion used for the temperature from degree Celsius to Kelvin is:

`K=273+^oC`

where,

`K` = temperature in Kelvin

`^oC` = temperature in centigrade

(a) As we are given the temperature in Fahrenheit is,
`87^oF`

Now we have to determine the temperature in degree Celsius.

`^oC=(^oF-32)* (5)/(9)`

`^oC=(87^oF-32)* (5)/(9)`

`^oC=30.5`

(b) As we are given the temperature in degree Celsius is,
`25^oC`

Now we have to determine the temperature in Kelvin.

`K=273+^oC`

`K=273+25`

`K=298`

Now we have to determine the temperature in degree Fahrenheit.

`^oC=(^oF-32)* (5)/(9)`

`25^oC=(^oF-32)* (5)/(9)`

`^oF=77`

(c) As we are given the temperature in Fahrenheit is,
`400^oF`

Now we have to determine the temperature in degree Celsius.

`^oC=(^oF-32)* (5)/(9)`

`^oC=(400^oF-32)* (5)/(9)`

`^oC=204.4`

Now we have to determine the temperature in Kelvin.

`K=273+^oC`

`K=273+204.4`

`K=477.4`

(d) As we are given the temperature in Kelvin, 77 K

Now we have to determine the temperature in degree Celsius.

`K=273+^oC`

`77=273+^oC`

`^oC=-196`

Now we have to determine the temperature in degree Fahrenheit.

`^oC=(^oF-32)* (5)/(9)`

`-196^oC=(^oF-32)* (5)/(9)`

`^oF=-320.8`

Answer 2

a. T = 87 F0

Temperature can be converted to celcius as follows:

F = (9 /5) C + 32

87 = (9 /5) C + 32

C = 30.55 C0

b. T = 25 C0

Temperature can be converted to kelvin as follows:

K = C + 273.15

= 30.55 + 273.15 = 303.7 K

F = (9 /5) C + 32

F = (9 /5) (25) + 32 = 77 F

c. T = 400 F

400 = (9 /5) C + 32

C = 204.44 C0

K = C + 273.15

K = 204.44 + 273.15 = 477.59 K

d . T = 77 K

77 K = C + 273.15

C = - 196.15 C0

F = (9 /5) C + 32

F = (9 /5) (- 196.15) + 32 = -321.07 F